Nowadays, Keith number is a topic that is becoming more and more relevant in our society. Since its appearance, it has generated great interest and debate among experts and the general population. Over time, Keith number has become a key element in different areas, from politics to popular culture. Its influence has become evident in various manifestations, causing a significant impact on the way we relate, communicate and make decisions. In this article, we will explore in depth the implications of Keith number and its impact on our daily lives.
In recreational mathematics, a Keith number or repfigit number (short for repetitive Fibonacci-like digit) is a natural number in a given number base with digits such that when a sequence is created such that the first terms are the digits of and each subsequent term is the sum of the previous terms, is part of the sequence. Keith numbers were introduced by Mike Keith in 1987.[1]
They are computationally very challenging to find, with only about 100 known.
Definition
Let be a natural number, let be the number of digits of in base , and let
Whether or not there are infinitely many Keith numbers in a particular base is currently a matter of speculation. Keith numbers are rare and hard to find. They can be found by exhaustive search, and no more efficient algorithm is known.[2]
According to Keith, in base 10, on average Keith numbers are expected between successive powers of 10.[3] Known results seem to support this.
A Keith cluster is a related set of Keith numbers such that one is a multiple of another. For example, in base 10, , , and are all Keith clusters. These are possibly the only three examples of a Keith cluster in base 10.[5]
Programming example
The example below implements the sequence defined above in Python to determine if a number in a particular base is a Keith number:
defis_repfigit(x:int,b:int)->bool:"""Determine if a number in a particular base is a Keith number."""ifx==0:returnTruesequence=y=xwhiley>0:sequence.append(y%b)y=y//bdigit_count=len(sequence)sequence.reverse()whilesequence<x:n=0foriinrange(0,digit_count):n=n+sequencesequence.append(n)returnsequence==x